2.1 Basic functions practice 1

$4x-5y+6=0$

$(x-1)(y+2)=3$

$y^2=x^2$

$y=3\cdot x^{-3}$

$x^2+2xy+y^2=1$

The domain is $\{x|x\geq0.5\}$
The range is $\{y|y\geq0\}$

The domain is $\{x|x\geq0.5\}$
The range is $\{y|y\leq0\}$

The domain is $\{x|x\geq1\}$
The range is $\{y|y\geq0\}$

The domain is $\{x|x\geq1\}$
The range is $\{y|y\leq0\}$

The domain is $\{1\}$
The range is $\{1\}$

The domain is $\{1\}$
The range is $\mathbb{R}$

The domain is $\mathbb{R}$
The range is $\{1\}$

The domain is $\mathbb{R}$
The range is $\mathbb{R}$

$\{y|y\leq5\}$

$\{y|y<5\}$

$\{y|y\geq5\}$

$\{y|y>5\}$

Domain: $\{x|x\neq1\}$
Range: $\{y|y\leq-7\}$

Domain: $\{x|x\geq1\}$
Range: $\{y|y<-7\}$

Domain: $\mathbb{R}$
Range: $\{y|y<-7\}$

Domain: $\mathbb{R}$
Range: $\{y|y\leq-7\}$

$\{y|y<3\}$

$\{y|\leq3\}$

$\{y|y<8\}$

$\{y|y\leq8\}$

$-5\notin R$

$-2\notin R$

$0\notin R$

$5\notin R$

None of the above

This relation is a function, but it is not one to one.

This relation is a function, and it is one to one.

This relation is a function, but is is not linear.

This relation is not a function.

$\{(0,1), (1,0), (2,0), (3,1)\}$

$\{(-1,5), (-2,4), (-3,-3), (-4,4)\}$

$\{(-1,1), (1,-1), (-1,3), (1,-3)\}$

$\{(2,\displaystyle{\frac{1}{2}}), (4,\displaystyle{\frac{1}{4}}), (8,\displaystyle{\frac{1}{8}}), (16,\displaystyle{\frac{1}{16}})\}$

$\{96, 99\}$

$\{-2, -3, -4, -5\}$

$\{x | x\in\mathbb{R}\}$

$\{-2, -3, -4, -5, 96, 99\}$

The relation of the figure is a one to one function.

The relation of the figure is a many to one function.

The relation of the figure is not a function because it is one to many.

The relation of the figure is not a function because it is many to many.